3m^2+72=-33m

Solution for 3m^2+72=-33m equation:

3m^2+72=-33m

We move all terms to the left:

3m^2+72-(-33m)=0

We get rid of parentheses

3m^2+33m+72=0

a = 3; b = 33; c = +72;
Δ = b2-4ac
Δ = 332-4·3·72
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-15}{2*3}=\frac{-48}{6}
=-8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+15}{2*3}=\frac{-18}{6}
=-3
$